my paginate function for DJango

作者：半瓶墨水链接：http://www.2maomao.com/blog/my-paginate-for-django/

感觉DJango的分页浏览不是很好用，需要先查出来再搞分页。
由于很常用，所以我自己写了个函数mypaginate（注意我的分页格式很固定，用”&page=2″这种方式）

在view中这样调用：

PAGE_SIZE = 10 #每页十个
params = "&keywords=%s&code_lang=%s" % (keywords, lang) #页面链接时候的额外参数
offset, page_navi, page_ex = mypaginate(request, total, PAGE_SIZE, params)

然后由render传给模板，模板中这么写：

{% if page_ex.prev %}
<a href="{{page_ex.first}}">第一页</a>
<a href="{{page_ex.prev}}">上一页</a>
{% else %}
第一页上一页
{% endif %}
{% for p, l in page_navi %}
<a id="p_{{p}}" href="/code/all/{{l}}">{{p}}</a>
{% endfor %}
{% if page_ex.max_page %}
... <a href="{{page_ex.last}}">{{page_ex.max_page}}</a>
{% endif %}
{% if page_ex.next %}
<a href="{{page_ex.next}}">下一页</a>
<a href="{{page_ex.last}}">最后页</a>
{% else %}
下一页最后页
{% endif %}

mypaginate函数源码：

Python语言: 自己写的paginate函数 for Django

 #发芽网的上下翻页那一块都是用的这个
 #blog: http://www.2maomao.com/blog/my-paginate-for-django/
 
 def mypaginate(request, total, pagesize, params=""):
     #get page info
     curr = int(request.GET.get('page', 1))
     #calculate the offset
     offset = (curr - 1) * pagesize
     if offset >= total:
         offset = total - 1
     if offset < 0:
         offset = 0
     #paginatize
     page_navi = []
     page_ex = {}
     max_page = (total - 1) / pagesize + 1
     start = curr - ((curr - 1) % 10)
     end = start + 10
     if end > max_page + 1:
         end = max_page + 1 #remember it's [start, end)
     elif max_page > end:
         page_ex['max_page'] = max_page
 
     for i in range(start, end):
         link = ("?page=%d&" % i) + params
         page_navi.append((i, link))
     if curr > 1:
         page_ex['first'] = ("?page=%d&" % 1) + params
         page_ex['prev'] = ("?page=%d&" % (curr - 1)) + params
     if curr < max_page:
         page_ex['next'] = ("?page=%d&" % (curr + 1)) + params
         page_ex['last'] = ("?page=%d&" % max_page) + params